6x^2+69x-36=0

Solution for 6x^2+69x-36=0 equation:

6x^2+69x-36=0

a = 6; b = 69; c = -36;
Δ = b2-4ac
Δ = 692-4·6·(-36)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(69)-75}{2*6}=\frac{-144}{12}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(69)+75}{2*6}=\frac{6}{12}
=1/2
$